document.write( "Question 759456: The graph of a quadratic function passes through B(4,6), and the zeros of the function are 5 and 6. Write an equation of the graph in general form.\r
\n" ); document.write( "\n" ); document.write( "This question makes no sense. If the x-intercepts are 5 and 6 how can there be a point (4,6) and still be a quadratic function. HELP please.
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Algebra.Com's Answer #462040 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Generally you would have y=ax^2+bx+c, and you are given the two zeros of the parabola. Try to narrow some of the equation using them.\r
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\n" ); document.write( "\n" ); document.write( "Point (5,0):
\n" ); document.write( "\"0=a%2A5%2A5%2Bb%2A5%2Bc\"
\n" ); document.write( "\"25a%2B5b%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "Point (6,0):
\n" ); document.write( "\"a%2A6%2A6%2Bb%2A6%2Bc=0\"
\n" ); document.write( "\"36a%2B6b%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "Also you were given point B(4,6):
\n" ); document.write( "\"a%2A4%2A4%2Bb%2A4%2Bc=6\"
\n" ); document.write( "\"16a%2B4b%2Bc=6\"\r
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\n" ); document.write( "\n" ); document.write( "NOW you have a system of three equations in three unknowns (yes, they should be constants but currently you do not know their values) of a, b, and c.
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\n" ); document.write( "SYSTEM:
\n" ); document.write( "\"16a%2B4b%2Bc=6\"
\n" ); document.write( "\"36a%2B6b%2Bc=0\"
\n" ); document.write( "\"25a%2B5b%2Bc=0\"
\n" ); document.write( "---------------------\r
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\n" ); document.write( "\n" ); document.write( "Can you take the rest of the solution process from there?\r
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\n" ); document.write( "\n" ); document.write( "Omitting the steps in solving that system, I found:
\n" ); document.write( "\"a=3\"
\n" ); document.write( "\"b=-33\"
\n" ); document.write( "\"c=90\"
\n" ); document.write( "EQUATION: \"highlight%28y=3x%5E2-33x%2B90%29\"
\n" ); document.write( "{solution checks as correct}.
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