document.write( "Question 65580: A plane flies 720mi agains a steady 30-mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10h, what is the plane's speed in still air?
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Algebra.Com's Answer #46204 by checkley71(8403)\"\" \"About 
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720/(X+30)+720/(X-30)=10
\n" ); document.write( "[720(X-30)+720(X+30)]/(X+30)(X-30)=10
\n" ); document.write( "(720X-21600+720X+21600)/X^2-900=10
\n" ); document.write( "1440X/X^2-900=10
\n" ); document.write( "10X^2-9000=1440X
\n" ); document.write( "10X^2-1440X-9000=0
\n" ); document.write( "X^2-144X-900=0
\n" ); document.write( "(x-150)(x+6)=0
\n" ); document.write( "x-150=0
\n" ); document.write( "x=150 mph for the plane in still air.
\n" ); document.write( "proof
\n" ); document.write( "720/180+720/120)=10
\n" ); document.write( "4+6=10
\n" ); document.write( "10=10
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\n" ); document.write( "MERRY CHRISTMAS
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