document.write( "Question 759397: If sinA= -12/13, Q3, and cosB=4/5, Q1, calculate the exact value:
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document.write( "a) sec (A-B)
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document.write( "b) cot (A-B) \n" );
document.write( "
Algebra.Com's Answer #462015 by lwsshak3(11628) ![]() You can put this solution on YOUR website! If sinA= -12/13, Q3, and cosB=4/5, Q1, calculate the exact value: \n" ); document.write( "a) sec (A-B) \n" ); document.write( "b) cot (A-B) \n" ); document.write( "*** \n" ); document.write( "sinA=-12/13 \n" ); document.write( "cosA=-5/13 (5-12-13 reference right triangle in Q3) \n" ); document.write( "tanA=sin/cos=12/5 \n" ); document.write( ".. \n" ); document.write( "cosB=4/5 \n" ); document.write( "sinB=3/5 (3-4-5 reference right triangle in Q1) \n" ); document.write( "tanB=sin/cos=3/4 \n" ); document.write( ".. \n" ); document.write( "Identity: \n" ); document.write( "a) \n" ); document.write( ".. \n" ); document.write( "Identity: \n" ); document.write( "b) \n" ); document.write( "computer check: \n" ); document.write( "sinA=-12/13 \n" ); document.write( "A≈67.38+180≈247.38º \n" ); document.write( "cosB=4/5 \n" ); document.write( "B≈36.87º \n" ); document.write( "A-B≈247.38-36.87≈210.51º \n" ); document.write( ".. \n" ); document.write( "cos(A-B)=cos(210.51º)≈-0.8615 \n" ); document.write( "exact value=-56/65≈-0.8615 \n" ); document.write( ".. \n" ); document.write( "tan(A-B)=tan(210.51º)≈0.5892 \n" ); document.write( "exact value=33/56≈0.5892 \n" ); document.write( " \n" ); document.write( " |