document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65584>Question 65584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The combined resistance of two resistors r1 and r2 in a parallel circuit is given by the formula:\r<BR>\n" );
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document.write( "Rt =   1<BR>\n" );
document.write( "    -------<BR>\n" );
document.write( "    1     1<BR>\n" );
document.write( "   --- + ---<BR>\n" );
document.write( "   R1     R2\r<BR>\n" );
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document.write( "Thank you for the help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46201 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46201\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> R=1/[(1/R1)+(1/R2)] SO IF THE TWO RESISTERS ARE 50 & 100 OHMS THEN<BR>\n" );
document.write( "R=1/[(1/50)+1/100)]<BR>\n" );
document.write( "R=1/[(2+1)/100]<BR>\n" );
document.write( "R=1/(3/100)<BR>\n" );
document.write( "R=1*(100/3)<BR>\n" );
document.write( "R=100/3<BR>\n" );
document.write( "R=33 1/3 OHMS.<BR>\n" );
document.write( "------------------------------------------<BR>\n" );
document.write( "IF BOTH RESISTERS ARE 500 OHMS THEN<BR>\n" );
document.write( "R=1/[(1/500)+(1/500)]<BR>\n" );
document.write( "R=1/(2/500)<BR>\n" );
document.write( "R=1*500/2<BR>\n" );
document.write( "R=500/2<BR>\n" );
document.write( "R=250 OHMS.<BR>\n" );
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document.write( "MERRY CHRISTMAS </SPAN>\n" );
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