document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65578>Question 65578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A passenger train can travel 325mi in the same amount of time a freight train takes to travel 200mi. If the speed of the passenger train is 25mi/h faster then the speed of the freight train, find the speed of each. <BR>\n" );
document.write( "Hos can this problem make sense with out knowing the actual time traveled or the speed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46200 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Freight train speed =x so the speed of the passenger train is x + 25<BR>\n" );
document.write( "Time = distance/speed so<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=325%2F%28x%2B25%29=200%2Fx ALIGN=MIDDLE  ALT=\"325%2F%28x%2B25%29=200%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Multiply each side by x<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=325x%2F%28x%2B25%29=200 ALIGN=MIDDLE  ALT=\"325x%2F%28x%2B25%29=200\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Multiply each side by (x+25)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=325x=200%28x%2B25%29 ALIGN=MIDDLE  ALT=\"325x=200%28x%2B25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=325x=200x%2B5000%29 ALIGN=MIDDLE  ALT=\"325x=200x%2B5000%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Subtract 200x from each side<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=125x=5000%29 ALIGN=MIDDLE  ALT=\"125x=5000%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x=5000/125<BR>\n" );
document.write( "=40 mile per hour and the passenger train speed is 65 miles per hour\r<BR>\n" );
document.write( "\n" );
document.write( "(A non algebra method would take the idea that the passenger train travels an extra 125 miles and is 25 miles per hour faster so the journey would take 5 hours. The speeds would therefore be 325/5 = 65 miles per hour and 200/5=40 miles per hour) </SPAN>\n" );
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