document.write( "Question 759249: How to get this ?\r
\n" ); document.write( "\n" ); document.write( "3/4p-1/3q=3
\n" ); document.write( "2q-p=10\r
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Algebra.Com's Answer #461955 by Alan3354(69443)\"\" \"About 
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How to get this ?\r
\n" ); document.write( "\n" ); document.write( "3/4p-1/3q=3
\n" ); document.write( "2q-p=10
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\n" ); document.write( "I'd use substitution.
\n" ); document.write( "p = 2q-10
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\n" ); document.write( "3/4p-1/3q=3
\n" ); document.write( "Multiply by 12
\n" ); document.write( "9p - 4q = 36
\n" ); document.write( "9(2q-10) - 4q = 36
\n" ); document.write( "etc
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