document.write( "Question 758998: find sum of infinite series 1/2^n
\n" ); document.write( "and series -1/2^n
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Algebra.Com's Answer #461947 by htmentor(1343)\"\" \"About 
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The nth term of a geometric series is normally written \"a_n+=+a%2Ar%5E%28n-1%29\"
\n" ); document.write( "For this series, we know that the infinite sum \"S+=+a%2F%281-r%29\"
\n" ); document.write( "The series \"%281%2F2%29%5En\" has a=1 and r=1/2. This series has terms 1/2, 1/4, 1/8...
\n" ); document.write( "The series above has terms 1, 1/2, 1/4, 1/8...
\n" ); document.write( "So the two series differ by 1.
\n" ); document.write( "The sum of the series \"a_n+=+%281%2F2%29%5E%28n-1%29+=+1%2F%281-%281%2F2%29%29+=+2\"
\n" ); document.write( "Therefore the sum of the series \"a_n+=+%281%2F2%29%5En+=+2-1+=+1\"
\n" ); document.write( "I'll leave it to you to figure out the other one.
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