document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=759247>Question 759247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of a sector of a circle, given the radius is 46mm and whose central angle is 120 degrees. use pi 3.14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461931 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Angle/360 = area of sector/Pi r^2<BR>\n" );
document.write( "120/360 = area of sector/Pi * 46^2<BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "Area of sector = 120 * 3.14* 46^2/ 360<BR>\n" );
document.write( "Area of sector = 2214.8 mm^2<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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