document.write( "Question 759113: Please help. \r
\n" ); document.write( "\n" ); document.write( "Solve for k in k/k+1=3/k^2-k-2
\n" ); document.write( "Answer Options:
\n" ); document.write( "A. k=-1 and k=2
\n" ); document.write( "B. k=-1 and k=3
\n" ); document.write( "C. k=3
\n" ); document.write( "D. k=-1\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #461861 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
Solve for k in k/k+1=3/k^2-k-2\r
\n" ); document.write( "\n" ); document.write( "factor denominator on right side of =\r
\n" ); document.write( "\n" ); document.write( "k /(k+1) = 3 / (k-2)*(k+1)\r
\n" ); document.write( "\n" ); document.write( "multiply both sides of = by (k-2)*(k+1)\r
\n" ); document.write( "\n" ); document.write( "k*(k-2) = 3\r
\n" ); document.write( "\n" ); document.write( "k^2 -2k -3 = 0\r
\n" ); document.write( "\n" ); document.write( "factor the above equation and we get\r
\n" ); document.write( "\n" ); document.write( "(k-3)*(k+1) = 0\r
\n" ); document.write( "\n" ); document.write( "to solve set (k-3) = 0 and (k+1) = 0\r
\n" ); document.write( "\n" ); document.write( "solutions are k = 3 and k = -1\r
\n" ); document.write( "\n" ); document.write( "and answer is B\r
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