document.write( "Question 65355: Solve for x:\r
\n" ); document.write( "\n" ); document.write( "a)y-x=6
\n" ); document.write( "b)1/x+7>-3 \n" ); document.write( "

Algebra.Com's Answer #46183 by funmath(2933) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:\r
\n" ); document.write( "\n" ); document.write( "a)y-x=6
\n" ); document.write( "y-y-x=6-y
\n" ); document.write( "-x=6-y
\n" ); document.write( "-1(-x)=-1(6-y)
\n" ); document.write( "x=-6+y <---this is fine
\n" ); document.write( "x=y-6 <---some teachers don't want leading negatives if possible, if that's the case switch the order.
\n" ); document.write( "b)1/x+7>-3
\n" ); document.write( "If this is what your mean:
\n" ); document.write( " $\"1%2Fx%2B7%3E-3\"$
\n" ); document.write( " $\"1%2Fx%2B7%2B3%3E-3%2B3\"$
\n" ); document.write( " $\"1%2Fx%2B10%3E0\"$ Now solve this like it's an equation.
\n" ); document.write( " $\"1%2Fx=-10\"$
\n" ); document.write( " $\"%281%2Fx%29%5E%28-1%29=%28-10%29%5E%28-1%29\"$
\n" ); document.write( " $\"x=-1%2F10\"$ <---That's a critical number along with 0, because it's undefined at 0.
\n" ); document.write( "(-infinity,-1/10) or (-1/10,0) or(0,infinity)
\n" ); document.write( "For (-infinity,-1/10) test -1
\n" ); document.write( " $\"1%2F-1%2B7%3E-3\"$
\n" ); document.write( " $\"-1%2B7%3E-3\"$
\n" ); document.write( " $\"6%3E-3\"$ True, accept this interval.
\n" ); document.write( "For (-1/10,0) test -1/11
\n" ); document.write( " $\"1%2F%28-1%2F11%29%2B7%3E-3\"$
\n" ); document.write( " $\"-11%2B7%3E-3\"$
\n" ); document.write( " $\"-4%3E-3\"$ <---false reject this interval
\n" ); document.write( "For (0,infinity) test 1
\n" ); document.write( " $\"1%2F1%2B7%3E-3\"$
\n" ); document.write( " $\"1%2B7%3E-3\"$
\n" ); document.write( " $\"8%3E-3\"$ <--true accept this interval
\n" ); document.write( "The solution is: (-infinity,-1/10)U(0,infinity)
\n" ); document.write( "Happy Calculating!!!
\n" ); document.write( " \n" ); document.write( "

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