document.write( "Question 759039: p^2+q^2=85, p-q=1,then p^2-q^2=? \n" ); document.write( "

Algebra.Com's Answer #461794 by stanbon(75887) $\"\"$ $\"About$

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p^2+q^2=85, p-q=1,then p^2-q^2=?
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\n" ); document.write( "p = 1+q
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\n" ); document.write( "Equation:
\n" ); document.write( "(1+q)^2 + q^2 = 85
\n" ); document.write( "1 + 2q + 2q^2 = 85
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\n" ); document.write( "2q^2 + 2q - 84 = 0
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\n" ); document.write( "q^2 + q - 42 = 0
\n" ); document.write( "----
\n" ); document.write( "Factor:
\n" ); document.write( "(q+7)(q-6) = 0
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\n" ); document.write( "q = 6 or q = -7
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\n" ); document.write( "Solve for \"p\"
\n" ); document.write( "p - q = 1
\n" ); document.write( "If q = 6, p = 7
\n" ); document.write( "If q = -7, p = -6
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\n" ); document.write( "p^2-q^2=?
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\n" ); document.write( "P^2 - q^2 = 6^2-7^2 = -13
\n" ); document.write( "OR
\n" ); document.write( "p^2 - q^2 = 7^2 - 6^2 = 13
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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