document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758997>Question 758997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 89 children were at the party, when 50 % of the girls and 20 % of the boys left, there were 55 children remaining at the party. How many boys were there at the party at first ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461773 by </B><A HREF=/tutors/aboutme.mpl?userid=malglu><B>malglu(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malglu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> at the start<BR>\n" );
document.write( " boys (b) + girls (g) = 89<BR>\n" );
document.write( "after some left, there are now<BR>\n" );
document.write( " 1/2 the original amount of girls and 4/5 of the original amount of boys left, and these equal 55 kids altogether.\r<BR>\n" );
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document.write( "if you write these out as simultaneous equations\r<BR>\n" );
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document.write( "89 = b+g<BR>\n" );
document.write( "55 = 1/2g + 4/5 b\r<BR>\n" );
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document.write( "then mutiply the second equation by 2\r<BR>\n" );
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document.write( "110 = g + 8/5b<BR>\n" );
document.write( "89 = g + b\r<BR>\n" );
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document.write( "now minus the second one from the first\r<BR>\n" );
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document.write( "21 = 3/5b<BR>\n" );
document.write( "multiply by 5, then divdide by 3 to get<BR>\n" );
document.write( "b=35 </SPAN>\n" );
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