document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758955>Question 758955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if three times the number is added to twice the same number, the result is the sum of thrice the number an 10. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461743 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number = x<BR>\n" );
document.write( "Three times the number + twice the number<BR>\n" );
document.write( "                 3x + 2x<BR>\n" );
document.write( "Thrice the number + 10<BR>\n" );
document.write( "                 3x + 10\r<BR>\n" );
document.write( "\n" );
document.write( "         3x + 2x = 3x + 10<BR>\n" );
document.write( "Collect like terms.<BR>\n" );
document.write( "Change signs as you cross equal sign.<BR>\n" );
document.write( "        3x + 2x - 3x = 10<BR>\n" );
document.write( "                   2x = 10<BR>\n" );
document.write( "                     x= 5\r<BR>\n" );
document.write( "\n" );
document.write( "   15 + 10 = 15 + 10<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );