document.write( "Question 758940: Two years ago, a man was 7 times as old as his son. In 3 years time, he will be only 4 times as old as son. Find the present age of the man and of his son. \n" ); document.write( "
Algebra.Com's Answer #461733 by Menjax(62)\"\" \"About 
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Defince unknowns
\n" ); document.write( "Let M = Man's current age
\n" ); document.write( "Let S = Son's current age
\n" ); document.write( "Dissect the question to get your equations
\n" ); document.write( "(M-2) = 7(S-2) #1
\n" ); document.write( "(M+3) = 4(S+3) #2
\n" ); document.write( "From #1 M = 7S-12
\n" ); document.write( "Sub above into #2
\n" ); document.write( "7S-9=4S+12
\n" ); document.write( "3S=21
\n" ); document.write( "S=7
\n" ); document.write( "Sub S into #1
\n" ); document.write( "M-2=7(7-2)
\n" ); document.write( "M=37\r
\n" ); document.write( "\n" ); document.write( "So the man's current age is 37 years old and his son's age is 7 years old
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