document.write( "Question 758637: 2logx-2=log (x-25) \n" ); document.write( "

Algebra.Com's Answer #461730 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
2logx-2=log (x-25)
\n" ); document.write( "2logx-log (x-25)=2
\n" ); document.write( " $\"log%28x%5E2%2F%28x-25%29%29=log%28100%29\"$
\n" ); document.write( " $\"%28x%5E2%29%2F%28x-25%29=100\"$
\n" ); document.write( "x^2=100x-2500
\n" ); document.write( "x^2-100x+2500=0
\n" ); document.write( "(x-50)^2=0
\n" ); document.write( "x=50 \n" ); document.write( "

\n" );