document.write( "Question 758896: Determine the equation of the hyperbola whose asymptotes are x±2y=0 and which passes through (4,3) \n" ); document.write( "
Algebra.Com's Answer #461726 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Determine the equation of the hyperbola whose asymptotes are x±2y=0 and which passes through (4,3) \n" ); document.write( "*** \n" ); document.write( "Hyperbola has a vertical transverse axis since it passes thru (4,3) \n" ); document.write( "Its standard form of equation: (y-k)^2/a^2-(x-h)^2/b^2=1, (h,k)=(x,y) coordinates of center \n" ); document.write( "Asymptotes are two straight line equations that intersect at center, y=mx+b, m=slope, b=y-intercept \n" ); document.write( "Equation of asymptote with positive slope: \n" ); document.write( "x-2y=0 \n" ); document.write( "2y=x \n" ); document.write( "y=x/2 \n" ); document.write( "m=1/2, b=0 \n" ); document.write( ".. \n" ); document.write( "Equation of asymptote with negative slope: \n" ); document.write( "x+2y=0 \n" ); document.write( "2y=-x \n" ); document.write( "y=-x/2 \n" ); document.write( "m=-1/2, b=0 \n" ); document.write( "This means center is at (0,0) \n" ); document.write( ".. \n" ); document.write( "slopes of asymptotes with vertical transverse axis \n" ); document.write( "=±a/b=±1/2 \n" ); document.write( "b=±2a \n" ); document.write( "b^2=4a^2 \n" ); document.write( ".. \n" ); document.write( "solving for a^2 and b^2 using coordinates of given point(4,3) \n" ); document.write( "(y-k)^2/a^2-(x-h)^2/b^2=1 \n" ); document.write( "y^2/a^2-x^2/4a^2=1 \n" ); document.write( "9/a^2-16/4a^2=1 \n" ); document.write( "9/a^2-4/a^2=1 \n" ); document.write( "5/a^2=1 \n" ); document.write( "a^2=5 \n" ); document.write( "b^2=4a^2=20 \n" ); document.write( "Equation: |