document.write( "Question 758757: if $2,000 is invested at 7% compounded
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document.write( "(A) annually (B) quarterly (C) monthly
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document.write( "what is the amount after 5 years? How much interest is earned?\r
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document.write( "Please show the steps taken to get the answers, so I can better understand how to solce future problems such as this.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #461656 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! if $2,000 is invested at 7% compounded \n" ); document.write( "(A) annually (B) quarterly (C) monthly \n" ); document.write( "what is the amount after 5 years? How much interest is earned? \n" ); document.write( "*** \n" ); document.write( "compound interest formula: A=P(1+i)^n, P=initial investment, i=interest rate per period, n=number of periods, A=amount after n years. \n" ); document.write( ".. \n" ); document.write( "For annual compounding: \n" ); document.write( "P=2000 \n" ); document.write( "i=7%/1=0.07 \n" ); document.write( "n=5*1=5 \n" ); document.write( "A=2000(1+.07)^5 \n" ); document.write( "A=2000(1.07)^5 \n" ); document.write( "A=2000(1.4026)=$2805 \n" ); document.write( ".. \n" ); document.write( "For quarterly compounding: \n" ); document.write( "P=2000 \n" ); document.write( "i=7%/4=0.0175 \n" ); document.write( "n=5*4=20 \n" ); document.write( "A=2000(1+.0175)^20 \n" ); document.write( "A=2000(1.0175)^20 \n" ); document.write( "A=2000(1.1448)=$2830 \n" ); document.write( ".. \n" ); document.write( "For monthly compounding: \n" ); document.write( "P=2000 \n" ); document.write( "i=7%/12=0.005833 \n" ); document.write( "n=5*12=60 \n" ); document.write( "A=2000(1+.005833)^60 \n" ); document.write( "A=2000(1.005833)^60 \n" ); document.write( "A=2000(1.4176)=$2835 \n" ); document.write( " |