document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758621>Question 758621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help I've been working on this for awhile now. thank you in advance.\r<BR>\n" );
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document.write( "Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p.  Use the given values of n and p to find the mean &#956; and standard deviation &#963;.  Also, use the range rule of thumb to find the minimum usual value &#956; - 2&#963; and the maximum usual value &#956; + 2&#963;\r<BR>\n" );
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document.write( "n=70, p=0.75\r<BR>\n" );
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document.write( " &#956; = <BR>\n" );
document.write( " &#963; =<BR>\n" );
document.write( " &#956; - 2&#963; =<BR>\n" );
document.write( " &#956; + 2&#963; = </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461594 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,\r<BR>\n" );
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document.write( "Since you have n = 70 and p = 0.75 and q = 1 - 0.75 = 0.25\r<BR>\n" );
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document.write( "Mean = &#956; = np<BR>\n" );
document.write( "&#963; = SQRT(n * p * q)\r<BR>\n" );
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document.write( "After you find the mean and standard deviation, you can plug into the two expressions.\r<BR>\n" );
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document.write( "Hope it helps you\r<BR>\n" );
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document.write( "John </SPAN>\n" );
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