document.write( "Question 758597: A 50% acid solution is mixed with a 25% acid solution to form a 40% acid solution. How many liters of the 25% acid solution are used to make 20 liters of the 40% acid solution? \r
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document.write( "\"50x +25(20-x)=40\" seems to be wrong. Help me please! \n" );
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Algebra.Com's Answer #461592 by John10(297)![]() ![]() You can put this solution on YOUR website! Hi,\r \n" ); document.write( "\n" ); document.write( "You have some good idea :)\r \n" ); document.write( "\n" ); document.write( "For this problem,\r \n" ); document.write( "\n" ); document.write( "You need to find 2 equations for a linear system.\r \n" ); document.write( "\n" ); document.write( "Let call x to be the amount of 50% acid and y to be the amount of 25% acid\r \n" ); document.write( "\n" ); document.write( "We know the total is 20 L, thus the first equation is x + y = 20\r \n" ); document.write( "\n" ); document.write( "Another equation would be about the mixture: 0.5x + 0.25y = 0.4(20) = 8\r \n" ); document.write( "\n" ); document.write( "So you have the system of 2 linear equations:\r \n" ); document.write( "\n" ); document.write( "x + y = 20 \n" ); document.write( "0.5x + 0.25y = 8\r \n" ); document.write( "\n" ); document.write( "You can solve for x and y ( which is the amount of 25% acid)\r \n" ); document.write( "\n" ); document.write( "If you need some more assistance, please email me.\r \n" ); document.write( "\n" ); document.write( "Thank you! \n" ); document.write( " |