document.write( "Question 758466: kx+y+z=1
\n" ); document.write( "x+ky+z=1
\n" ); document.write( "x+y+kz=1
\n" ); document.write( "find
\n" ); document.write( " the value of k \n" ); document.write( "
Algebra.Com's Answer #461579 by ankor@dixie-net.com(22740)\"\" \"About 
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kx+y+z=1
\n" ); document.write( "kx = 1-y-z
\n" ); document.write( "k = \"%28%281-y-z%29%29%2Fx\"
\n" ); document.write( ":
\n" ); document.write( "x+ky+z=1
\n" ); document.write( "ky = 1-x-z
\n" ); document.write( "k = \"%28%281-x-z%29%29%2Fy\"
\n" ); document.write( ":
\n" ); document.write( "x+y+kz=1
\n" ); document.write( "kz = 1-x-y
\n" ); document.write( "k = \"%28%281-x-y%29%29%2Fz\"
\n" ); document.write( " \n" ); document.write( "
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