document.write( "Question 758531: Find the coordinates of a point on a circle at the opposite end of the diameter from point A (-7,-1)? The circle's formula is (x+4)^2+(y-3)^2=25 \n" ); document.write( "

Algebra.Com's Answer #461538 by Edwin McCravy(20060) $\"\"$ $\"About$

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document.write( "(x-h)² + (y-k)² = r² has center (h,k) and radius r\r\n" );
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document.write( "compare your equation \r\n" );
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document.write( "(x+4)² + (y-3)² = 25 \r\n" );
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document.write( "to that and you see that\r\n" );
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document.write( "-h=+4, so h=-4\r\n" );
document.write( "-k=-3, so k=3\r\n" );
document.write( " r²=25, so r=5\r\n" );
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document.write( "Draw a horizontal line from (-7,-1) to a point directly below\r\n" );
document.write( "the center, then a vertical line from there to the center (4,3).\r\n" );
document.write( "The horizontal line is 3 units long and the vertical line is\r\n" );
document.write( "4 units long.  Then do the same from the center of the circle,\r\n" );
document.write( "3 units right from (4,3), then 4 units up, and you end up at\r\n" );
document.write( "the point (-1,7)\r\n" );
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document.write( "Edwin

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