document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758329>Question 758329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of each of the following.<BR>\n" );
document.write( "1. square whose sides are (x+1) in length<BR>\n" );
document.write( "2. triangle whose base is 5 1/2 in. and whose height is 2 1/4 in.\r<BR>\n" );
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document.write( "For #1, I tried it and got x^2+1<BR>\n" );
document.write( "For #2, I got 6 3/16 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461498 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of a square with sides (x + 1)<BR>\n" );
document.write( "= (x + 1)(x + 1) = x^2 + 2x + 1<BR>\n" );
document.write( "Area of a triangle whose base is 51/2ins<BR>\n" );
document.write( "and height 21/4 ins.<BR>\n" );
document.write( "= 1/2(51/2 + 21/4)<BR>\n" );
document.write( "= 1/2 (31/4)<BR>\n" );
document.write( "= 31/8<BR>\n" );
document.write( "= 3 7/8 ins^2<BR>\n" );
document.write( "Hope this heps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );