document.write( "Question 758487: Pls help me evaluate this Log32(0.0625) \n" ); document.write( "
Algebra.Com's Answer #461494 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your expression is:
\n" ); document.write( "log32(.0625)
\n" ); document.write( "let y = log32(.0625)
\n" ); document.write( "this is true if and only if 32^y = .0625
\n" ); document.write( "take the log of both sides of this equation to the base of 10 to get:
\n" ); document.write( "log10(32^y) = log10(.0625)
\n" ); document.write( "this becomes y * log10(32) = log10(.0625)
\n" ); document.write( "divide both sides of this equation by log10(32) to get:
\n" ); document.write( "y = log10(.0625) / log10(32)
\n" ); document.write( "since log10 is the LOG function of your calculator, you can use your calculator to find:
\n" ); document.write( "y = LOG(.0625) / LOG(32) to get:
\n" ); document.write( "y = -.8
\n" ); document.write( "32^-.8 = .0625 so it looks like y = -.8 is your answer.
\n" ); document.write( "your answer is:
\n" ); document.write( "log32(.0625) = -.8\r
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\n" ); document.write( "\n" ); document.write( "the general log properties that are employed in the solving of this problem are:\r
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\n" ); document.write( "\n" ); document.write( "y = logb(x) if and only if b^y = x
\n" ); document.write( "logb(x^a) = a * logb(x)
\n" ); document.write( "if x = y, then logb(x) = logb(y)\r
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\n" ); document.write( "\n" ); document.write( "logb means log to the base of b.
\n" ); document.write( "logb(x) means log of x to the base of b.\r
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