document.write( "Question 758336: a student has 55 coins worth a total of $7.35. each coin is either a nickel or a quarter. of x is the number of nickels, then x can be determined for the equation \n" ); document.write( "
Algebra.Com's Answer #461472 by ankor@dixie-net.com(22740)\"\" \"About 
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a student has 55 coins worth a total of $7.35.
\n" ); document.write( " each coin is either a nickel or a quarter.
\n" ); document.write( "If x is the number of nickels, then x can be determined for the equation
\n" ); document.write( ":
\n" ); document.write( "Let x = no. of nickels
\n" ); document.write( "total coins is 55, therefore
\n" ); document.write( "(55-x) = no. quarters
\n" ); document.write( ":
\n" ); document.write( ".05x + .25(55-x) = 7.35
\n" ); document.write( ".05x + 13.75 - .25x = 7.35
\n" ); document.write( ".05x - .25x = 7.35 - 13.75
\n" ); document.write( "-.20x = -6.40
\n" ); document.write( "x = -6.4/-.2
\n" ); document.write( "x = +32 nickels
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if this checks out: 55-32 = 23 quarters
\n" ); document.write( ".05(32) = 1.60
\n" ); document.write( ".25(23) = 5.75
\n" ); document.write( "-----------------
\n" ); document.write( "total$ = 7.35 \n" ); document.write( "
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