document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758417>Question 758417</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many negative real zeros are possible for a polynomial function f(x), given that f(&#8722;x) has 9 variations in sign? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461465 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 9 sign changes for f(-x), so there are at most 9 negative real zeros possible. </SPAN>\n" );
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