document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758321>Question 758321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Mom was born in 1943 and had a son in 1978, in the year 2013 she would be twice his age.  What is the formula to determine how old they would be when that would happen the next time?  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461454 by </B><A HREF=/tutors/aboutme.mpl?userid=Menjax><B>Menjax(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Menjax><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m=s+35<BR>\n" );
document.write( "m+35=s+70<BR>\n" );
document.write( "m=2s<BR>\n" );
document.write( "s=35 m=70\r<BR>\n" );
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document.write( "I think the question is asking when will the mom be double her sons age next?<BR>\n" );
document.write( "s=40 m=80\r<BR>\n" );
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document.write( "formula is M=2s<BR>\n" );
document.write( "y=ax+c<BR>\n" );
document.write( "m=as+c<BR>\n" );
document.write( "m=2s+c<BR>\n" );
document.write( "80=80+0<BR>\n" );
document.write( "m=2s </SPAN>\n" );
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