document.write( "Question 758352: Please help me solve the radical equation: sqrt (x+2) + sqrt (3x+7) = 1 \n" ); document.write( "
Algebra.Com's Answer #461438 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"sqrt+%28x%2B2%29+%2B+sqrt+%283x%2B7%29+=+1\"....square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2+%2B+2sqrt%28%28x%2B2%29%283x%2B7%29%29%2B3x%2B7+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"2sqrt%28%28x%2B2%29%283x%2B7%29%29%2B4x%2B9+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"2sqrt%28%28x%2B2%29%283x%2B7%29%29=-4x-9%2B+1\"\r
\n" ); document.write( "\n" ); document.write( "\"2sqrt%28%28x%2B2%29%283x%2B7%29%29=-4x-8\"\r
\n" ); document.write( "\n" ); document.write( "\"2sqrt%28%28x%2B2%29%283x%2B7%29%29%2F2=-4x%2F2-8%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28%28x%2B2%29%283x%2B7%29%29=-2x-4\"...square both sides\r
\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28%28x%2B2%29%283x%2B7%29%29%29%5E2=%28-2x-4%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%283x%2B7%29=4x%5E2%2B16x%2B16\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B7x%2B6x%2B14=4x%5E2%2B16x%2B16\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B13x%2B14=4x%5E2%2B16x%2B16\"\r
\n" ); document.write( "\n" ); document.write( "\"0=4x%5E2-3x%5E2%2B16x-13x%2B16-14\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x%2B2=0\"...write \"3x\" as \"2x%2Bx\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x%2Bx%2B2=0\".....group\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2Bx%29%2B%282x%2B2%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%28x%2B1%29%2B2%28x%2B1%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%28x%2B2%29=0\".......use zero product rule\r
\n" ); document.write( "\n" ); document.write( "if \"x%2B1=0\" => \"x=-1\"\r
\n" ); document.write( "\n" ); document.write( "if \"x%2B2=0\" => \"x=-2\"\r
\n" ); document.write( "\n" ); document.write( " only solution that works is \"highlight%28x=-2%29\" because it makes term \"sqrt+%28x%2B2%29\" equal to zero and term \"sqrt+%283x%2B7%29\" equal to \"1\"\r
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