document.write( "Question 758352: Please help me solve the radical equation: sqrt (x+2) + sqrt (3x+7) = 1 \n" ); document.write( "
Algebra.Com's Answer #461430 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
\"%0D%0Asqrt+%28x%2B2%29+%2B+sqrt+%283x%2B7%29+=+1%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0Asqrt+%28x%2B2%29%5E2++=+%281-sqrt+%283x%2B7%29%29%5E2%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0Ax%2B2=1-2+sqrt%283x%2B7%29%2B3x%2B7%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0A2x%2B6=2sqrt+%283x%2B7%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0Ax%2B3=-sqrt%283x%2B7%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0A%28x%2B3%29%5E2=%28-sqrt%283x%2B7%29%29%5E2%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0Ax%5E2%2B6x%2B9=3x%2B7%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0Ax%5E2%2B3x%2B2=0%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5B1%5D=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5B2%5D=-1\" (extraneous)
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