document.write( "Question 758299: Here is my question:\r
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document.write( "when p(x) is divided by x-1 the remainder is 1, and when divided by (x-2)(x-3) the remainder is 5. find remainder when P(X) is divided by (x-1)(x-2)(x-3).\r
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document.write( "here is part of my work:
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document.write( "let the quotient be Q(x), and let the remainder be ax+b
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document.write( "P(x)=(x-1)(x-2)(x-3)Q(X)+ax+b
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document.write( "P(1)=a*1+b=1 then a+b=1 (1)\r
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document.write( "then I don't know how to do with (x-2)(x-3) and the remainder is 5. Please help!\r
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document.write( "thanks
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Algebra.Com's Answer #461409 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "When you divide by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That gives you the sytem \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and finally \n" ); document.write( " \n" ); document.write( "The remainder when \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "There are infinite possibilities for \n" ); document.write( "In that case, \n" ); document.write( " |