document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758168>Question 758168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 5 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 331, find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461386 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First number = x<BR>\n" );
document.write( "Second number = 5x<BR>\n" );
document.write( "Third number = x + 100<BR>\n" );
document.write( " x + 5x + (x + 100) = 331<BR>\n" );
document.write( "           7x + 100 = 331<BR>\n" );
document.write( "                  7x = 231<BR>\n" );
document.write( "                   x = 33<BR>\n" );
document.write( "First number = 33<BR>\n" );
document.write( "Second number = 165<BR>\n" );
document.write( "Third number = 133<BR>\n" );
document.write( "         Total 331<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );