document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758267>Question 758267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains are 318 miles apart, and their speeds differ by 24 mph. Find the speed of each train if they are traveling toward each other and will meet in 3 hours. <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461354 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two trains are 318 miles apart, and their speeds differ by 24 mph. Find the speed of each train if they are traveling toward each other and will meet in 3 hours. <BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=speed of faster train<BR>\n" );
document.write( "x-24=speed of other(slower) train<BR>\n" );
document.write( "distance=travel time*speed<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3x+3(x-24)=318<BR>\n" );
document.write( "3x+3x-72=318<BR>\n" );
document.write( "6x=390<BR>\n" );
document.write( "x=65<BR>\n" );
document.write( "x-24=41<BR>\n" );
document.write( "speed of faster train=65 mph<BR>\n" );
document.write( "speed of other(slower) train=41 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );