document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65345>Question 65345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify (4a^3b^-3c^2)^3/(-2a^-2b^2c^-1)^4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46134 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4A^3B^-3C^2)^3/(-2A^-2B^2C^-1)^4 CUBE THE NUMERATOR AND RAISE THE DENOMINATOR BY THE FOURTH POWER THUS: <BR>\n" );
document.write( "(64A^6B^1C^5)/(16A^2B^6C^3) NOW FACTOR OUT ALL TERMS<BR>\n" );
document.write( "4A^4B^-5C^2<BR>\n" );
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document.write( "MERRY CHRISTMAS\r<BR>\n" );
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