document.write( "Question 758247: find the solution set of square root of (2t+4)= square root of (t-1) and check for extraneous solution if any? \n" ); document.write( "

Algebra.Com's Answer #461330 by tommyt3rd(5050) $\"\"$ $\"About$

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$\"%0D%0Asqrt%282t%2B4%29=+sqrt+%28t-1%29%0D%0A\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"%0D%0Asqrt%282t%2B4%29%5E2=+sqrt+%28t-1%29%5E2%0D%0A\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"%0D%0Aabs%282t%2B4%29=+abs%28t-1%29%0D%0A\"$ \r
\n" ); document.write( "\n" ); document.write( "leads to\r
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\n" ); document.write( "\n" ); document.write( "2t+4=t-1\r
\n" ); document.write( "\n" ); document.write( "t=-5
\n" ); document.write( "(extraneous unless we allow for imaginary numbers)\r
\n" ); document.write( "\n" ); document.write( "or\r
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\n" ); document.write( "\n" ); document.write( "2t+4=-(t-1)\r
\n" ); document.write( "\n" ); document.write( "3t=3\r
\n" ); document.write( "\n" ); document.write( "t=1
\n" ); document.write( "(extranoous)\r
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\n" ); document.write( "\n" ); document.write( "We see that over the reals this equation has no solution. Iver the complex numbers, x=-5\r
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\n" ); document.write( "\n" ); document.write( ":) \n" ); document.write( "

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