document.write( "Question 758092: the sum of the ages of the parents and the three children is decades over a century.
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document.write( "The father is twice as old as the eldest child.
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document.write( "When the eldest child was born, the sum of the parents age is 54.
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document.write( "When the youngest child was born, the sum of the parents age was 70.
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document.write( "In 38 years, the sum of the parents ages will be equal to the sum of the childrens ages.
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document.write( "How old is the second child?
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Algebra.Com's Answer #461316 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the sum of the ages of the parents and the three children is decades \n" ); document.write( "over a century. \n" ); document.write( ": \n" ); document.write( "f, m, a, b, c; (a is the oldest child) \n" ); document.write( "The father is twice as old as the eldest child. \n" ); document.write( "f = 2a \n" ); document.write( ": \n" ); document.write( "When the eldest child was born, the sum of the parents age is 54. \n" ); document.write( "(f-a) + (m-a) = 54, \n" ); document.write( "f + m - 2a = 54 \n" ); document.write( "we know that f = 2a \n" ); document.write( "2a + m - 2a = 54 \n" ); document.write( "m = 54 is mom's age \n" ); document.write( ": \n" ); document.write( "When the youngest child was born, the sum of the parents age was 70. \n" ); document.write( "(f-c) + (m-c) = 70, \n" ); document.write( "f + m - 2c = 70 \n" ); document.write( ": \n" ); document.write( "Use elimination with these two equations \n" ); document.write( "f + m - 2c = 70 \n" ); document.write( "f + m - 2a = 54 \n" ); document.write( "---------------subtraction eliminates f and m \n" ); document.write( "+2a - 2c = 16 \n" ); document.write( "simplify \n" ); document.write( "a - c = 8 \n" ); document.write( "or \n" ); document.write( "c = a - 8 \n" ); document.write( ": \n" ); document.write( "In 38 years, the sum of the parents ages will be equal to the sum \n" ); document.write( " of the children's ages. \n" ); document.write( "(f+38) + (m+38) = (a+38) + (b+38) + (c+38) \n" ); document.write( "combine the values \n" ); document.write( "f + m + 76 = a + b + c + 114 \n" ); document.write( "subtract 76 from both sides \n" ); document.write( "f + m = a + b + c + 38 \n" ); document.write( "Replace f with 2a \n" ); document.write( "2a + m = a + b + c + 38 \n" ); document.write( "subtract a from both sides and we have \n" ); document.write( "a + m = b + c + 38 \n" ); document.write( "replace c with (a-8) \n" ); document.write( "a + m = b + a - 8 + 38 \n" ); document.write( "subtract a from both sides \n" ); document.write( "m = b + 30 \n" ); document.write( "We know that mom is 54 \n" ); document.write( "54 = b + 30 \n" ); document.write( "b = 54 - 30 \n" ); document.write( "b = 24 is the 2nd child's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this mess out by assuming the total of their present ages is \n" ); document.write( "an even 10 (a decade) over 100 and a=30 \n" ); document.write( "f = 60 (2a) \n" ); document.write( "m = 54 \n" ); document.write( "a = 30 \n" ); document.write( "b = 24 (m-30) \n" ); document.write( "c = 22 (a-8) \n" ); document.write( "------- \n" ); document.write( "tot: 190\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |