document.write( "Question 758198: A certain metal is 20% tin. How many Kg of this metal must be mixed with 80 kg of a metal that is 70% tin to get a metal that is 50% tin?\r
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document.write( "Kg of Metal Rate Kg of tin
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document.write( "x .20 x
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document.write( "80 .70 x
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document.write( "x .50 x\r
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document.write( "What I have so far:\r
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document.write( ".20x+.7(80)=.5(x+?)?\r
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Algebra.Com's Answer #461300 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A certain metal is 20% tin. How many Kg of this metal must be mixed with 80 kg of a metal that is 70% tin to get a metal that is 50% tin? \n" ); document.write( "*** \n" ); document.write( "let x=amt of 20% tin to be mixed \n" ); document.write( "80+x=amt of 50% tin final mixture \n" ); document.write( "20%x+70%(80)=50%(80+x) \n" ); document.write( ".2x+56=40+.5x \n" ); document.write( "0.3x=16 \n" ); document.write( "x≈53.33 \n" ); document.write( "amt of 20% tin to be mixed≈53.33 Kg \n" ); document.write( " \n" ); document.write( " |