document.write( "Question 758199: The length of a rectangular sign is 5 feet longer than the width. If the sign’s area is 300 square feet, find it’s length and width. \n" ); document.write( "
Algebra.Com's Answer #461299 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangular sign is 5 feet longer than the width. If the sign’s area is 300 square feet, find it’s length and width. \n" ); document.write( "*** \n" ); document.write( "let x=width \n" ); document.write( "x+5=length \n" ); document.write( "area=length times width \n" ); document.write( "(x+5)x=300 \n" ); document.write( "x^2+5x-300=0 \n" ); document.write( "(x+20)(x-15)=0 \n" ); document.write( "x+20=0 \n" ); document.write( "x=-20 (reject, x>0) \n" ); document.write( "x=15 \n" ); document.write( "x+5=20 \n" ); document.write( ".. \n" ); document.write( "width=15 ft \n" ); document.write( "length=20ft \n" ); document.write( " |