document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758219>Question 758219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, im stuck on this problem<BR>\n" );
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document.write( "A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 40 pounds of a mixture worth $2.10 per pound. How many pounds of each should he use?\r<BR>\n" );
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document.write( "I don't know the exact formula to use to solve it. it is beginning algebra. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461290 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 40 pounds of a mixture worth $2.10 per pound. How many pounds of each should he use? <BR>\n" );
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document.write( "let x=lbs of peanuts to mix.<BR>\n" );
document.write( "let y=lbs of jelly beans to mix<BR>\n" );
document.write( "x+y=40<BR>\n" );
document.write( "y=(40-x)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3x+1.50y=40*2.10                                                <BR>\n" );
document.write( "3x+1.5(40-x)=40*2.1<BR>\n" );
document.write( "3x+60-1.5x=84<BR>\n" );
document.write( "1.5x=24<BR>\n" );
document.write( "x=16<BR>\n" );
document.write( "y=40-x=24<BR>\n" );
document.write( "lbs of peanuts to mix =16<BR>\n" );
document.write( "lbs of jelly beans to mix=24 </SPAN>\n" );
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