document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=758216>Question 758216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If there is 3 liters of 70% fruit juice, how much 20% fruit juice do you have to add to get a 60% fruit juice concentrate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461281 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461281\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If there is 3 liters of 70% fruit juice, how much 20% fruit juice do you have to add to get a 60% fruit juice concentrate?<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.70*3 + 0.20x = 0.60(3+x)<BR>\n" );
document.write( "------<BR>\n" );
document.write( "70*3 + 20x = 60*3 + 60x<BR>\n" );
document.write( "-40x = -10*3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "x = 3/4 liters (amt. of 20% juice needed)<BR>\n" );
document.write( "===================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );