document.write( "Question 758138: my 6th grader had this for homework they barely started beg. algebra solving for x. Don't know how to help him with the problem below. Please help\r
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document.write( "the math team decided to sell customized pocket protectors as a fundraiser. These were truly a hot item in our school, and $240 was raised. Cecily had originally suggested a price that was $2 lower for each item, but if the team had agreed to that price they would have had to sell 20 more pocket protectors to get the $240\r
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document.write( "How many pocket protectors did they actually sell? what was the price of each. \n" );
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Algebra.Com's Answer #461263 by htmentor(1343) You can put this solution on YOUR website! Let p = the original price \n" ); document.write( "Let n = the number sold \n" ); document.write( "Since the amount raised is $240, we have n*p = 240 \n" ); document.write( "If they had lowered the price by $2, they would have needed to sell 20 more to make $240. \n" ); document.write( "The equation for this is (n+20)(p-2) = 240 \n" ); document.write( "Solve for p in the 1st equation and substitute in the 2nd: \n" ); document.write( "(n+20)(240/n-2) = 240 \n" ); document.write( "If you perform the multiplication and simplify, your are left with \n" ); document.write( "n^2 + 20n - 2400 = 0 \n" ); document.write( "Factor: \n" ); document.write( "(n+60)(n-40) = 0 \n" ); document.write( "Take the positive solution, n = 40 \n" ); document.write( "So they sold 40 pocket protectors at a cost of $6 each \n" ); document.write( " |