document.write( "Question 758089: A small island is 4 miles from the nearest point P on the straight shoreline of a large lake. If a woman on the island can row a boat 2 miles per hour and can walk 3 miles per hour, where should the boat be landed in order to arrive at a town 12 miles down the shore from P in the least time? Let x be the distance between point P and where the boat lands on the lake shore. \r
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document.write( "(A) Enter a function T(x) that describes the total amount of time the trip takes as a function of the distance x.
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document.write( "T(x) = \r
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document.write( "(B) What is the distance x=c that minimizes the travel time? Note: The answer to this problem requires that you enter the correct units.
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document.write( "c = . \r
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document.write( "(C) What is the least travel time? Note: The answer to this problem requires that you enter the correct units.
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document.write( "The least travel time is . \r
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document.write( "(D) Recall that the second derivative test says that if T′(c)=0 and T′′(c)>0, then T has a local minimum at c. What is T′′(c)?
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document.write( "T′′(c) =
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Algebra.Com's Answer #461262 by KMST(5328)![]() ![]() You can put this solution on YOUR website! The distance walked would be (12-x) miles. \n" ); document.write( "The distance rowed would be \n" ); document.write( "(A) \n" ); document.write( " \n" ); document.write( "(B) T'(x) = \n" ); document.write( " \n" ); document.write( "The approximate value is \n" ); document.write( "Since you are entering an answer, the expected answer may be \"3.6 miles\", but I would not know what format will be accepted. Maybe \"miles\" must be abreviated. Maybe spaces are not accepted, and the computer wants \"c=3.58mi\" for an answer. Maybe an answer starting with \"c=\" is not accepted. \n" ); document.write( " \n" ); document.write( "(C) The least travel time is \n" ); document.write( "I calculated \n" ); document.write( " \n" ); document.write( "(D) T\"(x) = \n" ); document.write( "I calculated T\"(c) = \n" ); document.write( "I see no reason to make us calculate that. Finding that T(c)=0, while T(x)<0 for x < c and T(x)>0 for x > c proves that T(x) decreases for x < c and increases for x > c, so there is a minimum at x=c. \n" ); document.write( " |