document.write( "Question 65556: Um..for f(x)=1/x^2-2x-8 I need to find the interval/intervals where f(x)<0 and I cant seem to figure it out. \n" ); document.write( "
Algebra.Com's Answer #46124 by stanbon(75887)\"\" \"About 
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for f(x)=1/x^2-2x-8 I need to find the interval/intervals where f(x)<0
\n" ); document.write( "f(x)=1/(x-4)(x+2)
\n" ); document.write( "You have vertical asymptotes at x=-2 and at x=4
\n" ); document.write( "Draw a number line.
\n" ); document.write( "Mark x=-2 and x=4 on the line
\n" ); document.write( "That breaks the line into 3 intervals;
\n" ); document.write( "Determine if f(x)<0 in each of those intervals, as follows.
\n" ); document.write( "If x=-10 f(-10)=1/(-)(-) which is positive; so no solutions in (-inf,-2)
\n" ); document.write( "If x=0 f(0)=1/(-)(+) which is negative; so (-2,4) is part of the solution
\n" ); document.write( "If x=10 f(10)=1/(+)(+) which is positive; so no solutions in (4,inf)
\n" ); document.write( "SOLUTION: -2\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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