document.write( "Question 65556: Um..for f(x)=1/x^2-2x-8 I need to find the interval/intervals where f(x)<0 and I cant seem to figure it out. \n" ); document.write( "
Algebra.Com's Answer #46124 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! for f(x)=1/x^2-2x-8 I need to find the interval/intervals where f(x)<0 \n" ); document.write( "f(x)=1/(x-4)(x+2) \n" ); document.write( "You have vertical asymptotes at x=-2 and at x=4 \n" ); document.write( "Draw a number line. \n" ); document.write( "Mark x=-2 and x=4 on the line \n" ); document.write( "That breaks the line into 3 intervals; \n" ); document.write( "Determine if f(x)<0 in each of those intervals, as follows. \n" ); document.write( "If x=-10 f(-10)=1/(-)(-) which is positive; so no solutions in (-inf,-2) \n" ); document.write( "If x=0 f(0)=1/(-)(+) which is negative; so (-2,4) is part of the solution \n" ); document.write( "If x=10 f(10)=1/(+)(+) which is positive; so no solutions in (4,inf) \n" ); document.write( "SOLUTION: -2 \n" ); document.write( "Stan H. |