document.write( "Question 758052: The given equation is either linear or equivalent to a linear equation. Solve the equation.\r
\n" ); document.write( "\n" ); document.write( " z/6=((3/10)z)+2\r
\n" ); document.write( "\n" ); document.write( "So far I have tried ... \r
\n" ); document.write( "\n" ); document.write( "0=((3/10)z)+2-(z/6)
\n" ); document.write( "0=z+2-(z/6)
\n" ); document.write( "-12=z-z\r
\n" ); document.write( "\n" ); document.write( "I've also tried ... \r
\n" ); document.write( "\n" ); document.write( "z=((3/10)z)+12
\n" ); document.write( "0=((3/10)z)+12-z
\n" ); document.write( "-12=((3/10)z)-z
\n" ); document.write( "-12/(-7/10)=((-7/10)z)/(-7/10)
\n" ); document.write( "-120/-7=z\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #461199 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
z/6=((3/10)z)+2
\n" ); document.write( "----
\n" ); document.write( "Just a suggestion::
\n" ); document.write( "When you have fractions, get rid of them:
\n" ); document.write( "---
\n" ); document.write( "Multiply thru by 60 to get:
\n" ); document.write( "10z = 6*(3z) + 120
\n" ); document.write( "----
\n" ); document.write( "10z = 18z + 120
\n" ); document.write( "---
\n" ); document.write( "6z = -120
\n" ); document.write( "---
\n" ); document.write( "z = -20
\n" ); document.write( "====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );