document.write( "Question 758052: The given equation is either linear or equivalent to a linear equation. Solve the equation.\r
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document.write( " z/6=((3/10)z)+2\r
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document.write( "So far I have tried ... \r
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document.write( "0=((3/10)z)+2-(z/6)
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document.write( "0=z+2-(z/6)
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document.write( "-12=z-z\r
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document.write( "I've also tried ... \r
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document.write( "z=((3/10)z)+12
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document.write( "0=((3/10)z)+12-z
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document.write( "-12=((3/10)z)-z
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document.write( "-12/(-7/10)=((-7/10)z)/(-7/10)
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document.write( "-120/-7=z\r
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document.write( "
Algebra.Com's Answer #461199 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! z/6=((3/10)z)+2 \n" ); document.write( "---- \n" ); document.write( "Just a suggestion:: \n" ); document.write( "When you have fractions, get rid of them: \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 60 to get: \n" ); document.write( "10z = 6*(3z) + 120 \n" ); document.write( "---- \n" ); document.write( "10z = 18z + 120 \n" ); document.write( "--- \n" ); document.write( "6z = -120 \n" ); document.write( "--- \n" ); document.write( "z = -20 \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |