document.write( "Question 758052: The given equation is either linear or equivalent to a linear equation. Solve the equation.\r
\n" );
document.write( "\n" );
document.write( " z/6=((3/10)z)+2\r
\n" );
document.write( "\n" );
document.write( "So far I have tried ... \r
\n" );
document.write( "\n" );
document.write( "0=((3/10)z)+2-(z/6)
\n" );
document.write( "0=z+2-(z/6)
\n" );
document.write( "-12=z-z\r
\n" );
document.write( "\n" );
document.write( "I've also tried ... \r
\n" );
document.write( "\n" );
document.write( "z=((3/10)z)+12
\n" );
document.write( "0=((3/10)z)+12-z
\n" );
document.write( "-12=((3/10)z)-z
\n" );
document.write( "-12/(-7/10)=((-7/10)z)/(-7/10)
\n" );
document.write( "-120/-7=z\r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #461197 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! Solution\r \n" ); document.write( "\n" ); document.write( "z/6=((3/10)z)+2 \r \n" ); document.write( "\n" ); document.write( "Multiply by 6\r \n" ); document.write( "\n" ); document.write( "z = (18/10)z+12\r \n" ); document.write( "\n" ); document.write( "(18/10-1)z = -12\r \n" ); document.write( "\n" ); document.write( "(8/10)z = -12\r \n" ); document.write( "\n" ); document.write( "z = -12(10)/8\r \n" ); document.write( "\n" ); document.write( "z = -15\r \n" ); document.write( "\n" ); document.write( "If you need more help with math questions/assignments/tests \n" ); document.write( "You can ask me more using this e-mail (mthman@gmail.com) or you can visit my site: \n" ); document.write( "http://mathshelp-online.com/ \n" ); document.write( "(Payment is using paypal) \n" ); document.write( " |