document.write( "Question 757984: A rain gutter is made from sheets of aluminum that are\r
\n" ); document.write( "\n" ); document.write( "12 inches wide by turning up the edges to form right angles.\r
\n" ); document.write( "\n" ); document.write( "Determine the depth of the gutter that will maximize its\r
\n" ); document.write( "\n" ); document.write( "cross-sectional area and allow the greatest amount of water to flow.\r
\n" ); document.write( "\n" ); document.write( "What is the maximum cross-sectional area?
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Algebra.Com's Answer #461165 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A rain gutter is made from sheets of aluminum that are
\n" ); document.write( "12 inches wide by turning up the edges to form right angles.
\n" ); document.write( "Determine the depth of the gutter that will maximize its
\n" ); document.write( "cross-sectional area and allow the greatest amount of water to flow.
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\n" ); document.write( "Let the height be \"x\"
\n" ); document.write( "Then base is 12-2x
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\n" ); document.write( "Area = x(12-2x) = -2x^2 + 12x
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\n" ); document.write( "Maximum of this parabola occurs when x = -b/(2a) = -12/(-4) = 3
\n" ); document.write( "That is the depth of gutter.
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\n" ); document.write( "That cross-section area is x(12-x) = 3*9 = 27 sq in.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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