document.write( "Question 65537This question is from textbook An Incremental Development
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\n" ); document.write( "\n" ); document.write( "6 times the square root of 7/5 - 2 times the square root of 5/7 - 3 times the square root of 140
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Algebra.Com's Answer #46116 by stanbon(75887)\"\" \"About 
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Simplify
\n" ); document.write( "6 times the square root of 7/5 - 2 times the square root of 5/7 - 3 times the square root of 140
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\n" ); document.write( "[6sqrt7/sqrt5] - 2[sqrt5/sqrt7] - 3[2sqrt35]
\n" ); document.write( "= [ (6/5)sqrt35] - [(2/7)sqrt35] - [6sqrt35]\r
\n" ); document.write( "\n" ); document.write( "=[6/5 - 2/7 - 6]sqrt35
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\n" ); document.write( "=[32/35 - 6]sqrt35
\n" ); document.write( "=[-178/35]sqrt35
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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