document.write( "Question 757973: If three spherical balls of wax with radius r are packed into a cylinder also with radius r, and the wax is melted down to what depth will the cylinder be filled. Answer needs to being terms of r. I am stumped and would appreciate the help. Thank you \n" ); document.write( "
Algebra.Com's Answer #461159 by stanbon(75887)\"\" \"About 
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If three spherical balls of wax with radius r are packed into a cylinder also with radius r, and the wax is melted down to what depth will the cylinder be filled. Answer needs to being terms of r.
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\n" ); document.write( "Volume of each ball is (4/3)pi*r^3
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\n" ); document.write( "Total volume of the 3 balls is (4pi*r^3)
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\n" ); document.write( "Width of the cylinder is 2r.
\n" ); document.write( "Area of the base is pi^r^2
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\n" ); document.write( "Volume of the melted wax is (area of the base)(height)= (pi*r^2)h
\n" ); document.write( "Volume of the melted was is ALSO 4pi*r^3
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\n" ); document.write( "Equation:
\n" ); document.write( "(pi*r^2)h = 4pi*r^3
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\n" ); document.write( "h = 4r (That is the depth of the wax)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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