document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757839>Question 757839</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist must mix 8 liters of a 70% solution of potassium chloride with some 40% solution to get a mixture that is a 50% solution. How much of the 40% solution should be use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461129 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 40% solution needed<BR>\n" );
document.write( "Now we know that the amount of pure potassium chloride that exists before the mixture takes place(8*0.70+0.40x)has to equal the amount of pure potassium chloride that exists after the mixture takes place(0.50(8+x)). Sooo<BR>\n" );
document.write( "8*0.70+0.40x=0.50(8+x)<BR>\n" );
document.write( "5.6+0.40x=4+0.50x subtract 4 and also 0.40x from each side<BR>\n" );
document.write( "5.6-4=0.50x-0.40x<BR>\n" );
document.write( "1.6=0.1x<BR>\n" );
document.write( "x=16 liters ---amount of 40% solution needed<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "8*0.70+0.40*16=0.50*24<BR>\n" );
document.write( "5.6+6.4=12<BR>\n" );
document.write( "12=12<BR>\n" );
document.write( "Hope this helps---ptaylor<BR>\n" );
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