document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=754218>Question 754218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Beth is twice as old as Donna. The sum of their ages is 54. Find their ages ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461098 by </B><A HREF=/tutors/aboutme.mpl?userid=lenny460><B>lenny460(1073)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lenny460><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lenny460><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Beth is twice as old as Donna. The sum of their ages is 54. Find their ages ?\r<BR>\n" );
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document.write( "Let the age of Donna be x\r<BR>\n" );
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document.write( "Let the age of Beth be 2x\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "2x + x = 54\r<BR>\n" );
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document.write( "3x = 54\r<BR>\n" );
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document.write( "Divide each side by 3\r<BR>\n" );
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document.write( "3x/3 = 54/3\r<BR>\n" );
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document.write( "x = 18\r<BR>\n" );
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document.write( "2x = 18 * 2 = 36\r<BR>\n" );
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document.write( "Answer:\r<BR>\n" );
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document.write( "Donna is 18 years old and\r<BR>\n" );
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document.write( "Beth is 36 years old.\r<BR>\n" );
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document.write( "Lennox Obuong<BR>\n" );
document.write( "Algebra Tutor<BR>\n" );
document.write( "Nairobi, Kenya<BR>\n" );
document.write( "Email: lennoxobuong@yahoo.com </SPAN>\n" );
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