document.write( "Question 757790: Substitution:
\n" ); document.write( "2x + y = 10
\n" ); document.write( "y = 8 - x
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Algebra.Com's Answer #461097 by lenny460(1073)\"\" \"About 
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Substitution:
\n" ); document.write( "2x + y = 10
\n" ); document.write( "y = 8 - x\r
\n" ); document.write( "\n" ); document.write( "Substitute y = 8 - x into equation (1).\r
\n" ); document.write( "\n" ); document.write( "2x + y = 10\r
\n" ); document.write( "\n" ); document.write( "2x + (8 - x) = 10\r
\n" ); document.write( "\n" ); document.write( "2x + 8 - x = 10\r
\n" ); document.write( "\n" ); document.write( "2x - x = x\r
\n" ); document.write( "\n" ); document.write( "x + 8 = 10\r
\n" ); document.write( "\n" ); document.write( "Subtract 8 from each side of the equation.\r
\n" ); document.write( "\n" ); document.write( "x + 8 - 8 = 10 - 8\r
\n" ); document.write( "\n" ); document.write( "x = 2\r
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\n" ); document.write( "\n" ); document.write( "Substitue x = 2 into equation (1).\r
\n" ); document.write( "\n" ); document.write( "2x + y = 10\r
\n" ); document.write( "\n" ); document.write( "2(2) + y = 10\r
\n" ); document.write( "\n" ); document.write( "4 + y = 10\r
\n" ); document.write( "\n" ); document.write( "Subtract 4 from each side of the equation.\r
\n" ); document.write( "\n" ); document.write( "4 + y - 4 = 10 - 4\r
\n" ); document.write( "\n" ); document.write( "y = 6\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "y = 8 -x\r
\n" ); document.write( "\n" ); document.write( "6 = 8 - 2\r
\n" ); document.write( "\n" ); document.write( "6 = 6\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "x = 2 and\r
\n" ); document.write( "\n" ); document.write( "y = 6\r
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\n" ); document.write( "\n" ); document.write( "Lennox Obuong
\n" ); document.write( "Algebra Tutor
\n" ); document.write( "Nairobi, Kenya
\n" ); document.write( "Email: lennoxobuong@yahoo.com
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