document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757750>Question 757750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in triangle abc, ab=16, ac=24, bc=16, and ad is an angle bisector. find the ratio of the area of triangle abd to the triangle acd. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461070 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the angle bisector of an angle of the triangle divides the opposite side with a ratio proportionate to corresponding sides<BR>\n" );
document.write( "so here <BR>\n" );
document.write( "Bd/CD=AB/Ac .........1<BR>\n" );
document.write( "now the ratio of areas=ABD/ACD=[(1/2)BD*h]/[(1/2)CD*h]   {h=height of the triangles being same for same vertex}<BR>\n" );
document.write( "so ABD/ACD=BD/CD=AB/Ac=16/24=2/3 (use eqn 1 above) </SPAN>\n" );
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